What is the solubility of M(OH)2 in pure water? This question was asked by many people. To answer that question, we need to know what m(oh)2 is first. M(OH)2 is a compound with a chemical formula of 2HgO. It’s also known as mercury (II) oxide and mercuric oxide. So what does it mean when someone asks “what is the solubility of M(OH)2 in pure water?” Well, this person wants to know how much can dissolve into one liter (or 1000 milliliters or mL). The answer will depend on temperature and other factors, so let’s find out!
Solubility is defined as the maximum amount of solute that can dissolve in a solvent, such as water. The solubility of M(OH)2 in pure water is about 4g/100mL. The solubility of any substance refers to how much it can dissolve into a solvent at a given temperature. There are many factors that contribute to the solubility of substances, and these include: temperature, pressure, chemical properties and type of solvent.
The solubility of M(OH)2 in pure water can be found by using the following equation. 𝑥=𝐿/𝑡∙𝐷, where x = amount dissolved (g), y = molarity (mol/L), and z = volume (L).
MOH is not solvable in water. M(OH)2 is soluble in water.
MMOH = monomolecular oxide hydrate (1) M-O-H group +
2HO molecules from 1 molecule of H2O + 2 e-
99% can be obtained by reacting with NaOH to form NaIO3 which then reacts with HCl to make H3O+ and O= ions and I- ions as well as the lye like compound HO, also called sodium hypochlorite or bleach, a white solid not found in nature that also occurs from electrolysis of NaCl solution using an electric current; this substance; has a low decomposition range (-38 deg)