What Is the Equivalent Capacitance of the Three Capacitors in the Figure

138

faThis is a question that you may have never pondered before, but it is actually really easy to answer. All we need to do is use the formula:
C = C1 + C2 + C3/n so in this case the equivalent capacitance would be equal to 3uF.

The three capacitors in the figure are all 10 microfarads each. To find the equivalent capacitance of these three capacitors, use this formula:
C=1/(1/C1+ 1/C2+ 1/C3)

This equation is telling you that the equivalent capacitance (or total) can be found by adding up what each individual capacitor would have if it were alone. In other words, C = C1 + C2 + C3

The three capacitors are labeled C1, C2 and C3. The total equivalent capacitance can be found by adding up all of their individual values. For example, if you have a 10 microfarad capacitor (C1) and a 5 microfarad capacitor (C2), then your total equivalent capacitance would be 15 microfarads. If you had two 10 microfarad caps (C1=10uF and C2=10uF), then your total would be 20 uF.

The equivalent capacitance of three parallel plate capacitors connected to a battery is shown.

Answer 1:

A = 0.2 Fuch x 10-8F/cm x 1 cm = 20 nF
B= 0.1 Fuch x 10-4F/cm x 1 cm = 100 pF
C= -0.1 Fuchx10-6oF/cmx1 cm=-100pH
so equivalent capacitance: 200nf for (A+B) and C = -100pH for C because they have the same denominator in their units so A+B=200 and C-C=-100, etcetera. I’m not sure how to make this easier to understand—I had a hard time figuring out the answer myself! You can multiply

Answer 2: The equivalent capacitance of the three capacitors in the figure is
Ceq = 1 / (1/C1 + 1/C2 + 1/C3)